![]() ![]() Incidentally, this is exactly how a straw works. If you built a container taller than 10 meters above the surface, you would just have water vapor above that height (at least that's what I think would happen). Since the atmospheric pressure is equivalent to the pressure at a water depth of 10 meters, this glass water column could rise 10 meters-but no higher. ![]() This means the force pushing down at A is greater than at B and the water is gets pushed up by the atmosphere. Instead, the air pressure above the water within the glass is reduced by removing some of the air. So why does the water get sucked up into the glass? Simple-it doesn't. This is the only way to make the sum of the forces zero (vector). The only way this can work is if the water pressure at point C is greater than the water pressure at A and B. Here there must be even more downward force because there is more water above it pushing down. † † margin: y y x - 2 - 1 1 2 - 2 - 1 1 2 50 water line not to scale d ( y ) = 50 - y Figure 6.5.8: Measuring the fluid force on an underwater porthole in Example 6.5.4.You'll notice point C. The truth is that it is not, hence the survival tips mentioned at the beginning of this section. This is counter-intuitive as most assume that the door would be relatively easy to open. Most adults would find it very difficult to apply over 500 lb of force to a car door while seated inside, making the door effectively impossible to open. Using the weight-density of water of 62.4 lb/ft 3, we have the total force as We adopt the convention that the top of the door is at the surface of the water, both of which are at y = 0. ![]() Its length is 10 / 3 ft and its height is 2.25 ft. SolutionThe car door, as a rectangle, is drawn in Figure 6.5.7. ![]()
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